vikas askiitian expert
Last Activity: 13 Years ago
electric field is a vector quantity so it can be broken into components ,
Ea is electric field by charge which is placed at vertex A
Eb is electric field by charge which is placed at vertex B
now , Ea & Eb both can be divided into two components ,
for Ea two components are Eacos@ & Easin@
for Eb two components are Ebcos@ & Ebsin@
now , it is clear that Eb sin@ is in opposite direction to Easin@ so they will cancel the effect of each other but
on other side Eacos@ & Ebcos@ are acting olong same direction so they will be add up to give total
electric field E = Eacos@ + Ebcos@
instead of all these one other method can be used for this particular problem , see both charges are of same magnitude
but opposite sign so this system will behave as a dipole & for this we can use direct formula
E(equitorial) = kp/(a2+x2)3/2
here p(dipole moment) = q(2a)
x = perpendicular distance
2a is distance bw charges