Why dF/dq is equal to zero for the force to be maximum in the problem below:A charge Q is divided into two parts of qand Q-q if the coulomb repulsion between them when they are seprated is to be maximum the ratio of Q/q should be
shivam agarwal , 11 Years ago
Grade 12
4 Answers
Mujahid Ahmed
Last Activity: 11 Years ago
It''s a basic result. For a point to be local maximum, the tangent at that point must be zero. Tangent is given by dF/dQ.
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saurabh gupta
Last Activity: 11 Years ago
R/21/2
FITJEE
Last Activity: 11 Years ago
IT IS BECAUZ THE AREA UNDER THE CURVE OF FORCE VS CHARGE GRAPH GIVE POTENTIAL AND DF/DQ GIVE TANGENT AT A PARTICULAR POINT AND IF SLOPE OF TANGENT AT A POINT IS 0 OR MINIMUM THEN FORCE WILL BE MAXXXXXXXXX..........
Abhishek Sharma
Last Activity: 5 Years ago
In application of derivatives we have studied that . If we have to find maximum value ex :
y = x^2+x+1
dy/dx = 2x+1
and dy/dx = 0
x = ½
And dy/dx = tan z ,where z is an angle formed with x axis.
At any point the graph of this equation it forms straight line which shows that
dy/dx = 0
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