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A 3x10-6 F capacitor is charged to a potential of 300 V and a 2 x10-6F capacitor is charged to 200 V. The capacitors are then connected in parallel with plates of opposite polarity joined together. What amount of charge will flow when the plates are so connected?

noogler , 9 Years ago
Grade 12th pass
anser 3 Answers
Shubham Singh

Last Activity: 9 Years ago

1.2 x 10-4 C of charge will flow

noogler

Last Activity: 9 Years ago

can u plz exp...........
i didnt get it

Shubham Singh

Last Activity: 9 Years ago

first of all calculate the initial charges on each capacitor(suppose q1 and q2)
then when they are connected together so charge will flow till they are at same potential.
let q be charge flown.
so, q1 – q = q2 + q
         c1          c2

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