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a charge q is disturbed over 2 hallow spheres of raddi r and R(R>r) such that surface densites are equal fin potential at the common centre

sai sandeep , 6 Years ago
Grade 12th pass
anser 1 Answers
Khimraj

Last Activity: 6 Years ago

Let the charge on sphere of radius r is q1 then charge on sphere of radius R is q2 = q-q1.
Acccording to question surface charge density of both sphere are equal.
So (q1/4πr2) = (q-q1)/4πR2
Solving above equation q1 = q(r2)/(r2+R2)
and q2 = q – q1 = q(R2)/(r2+R2)
Potential at there common centre V = Kq1/r + Kq2/R
putting value of q1 and q2
V = Kq(r +R)/(r2+R2).
Hope it clears. If still have doubt you can ask me. If you like answer then  please approve it. 

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