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A conducting sphere of radius R carrying charge Q is connected to an uncharged conducting sphere of radius 2R .The charge that flows between them is

Rankush , 5 Years ago
Grade 11
anser 2 Answers
Arun

Last Activity: 5 Years ago

We know that charge will flow between them till the potential becomes same on both spheres.
Let us assume that a charge x flows between them
charge on larger sphere will be x and charge on smaller sphere will be Q - x
Potential on smaller sphere = k (Q - x) / R
Potential on larger sphere = k x /2R
Equating the potentials
k (Q - x) / R = k x /2R
Q - x = x/2
3x/2 = Q
x = 2Q/3
Thus a charge of 2Q/3 will flow between them
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However if you consider them concentric spheres, such that smaller sphere lies inside the larger sphere. Then potential on inner sphere will be always greater. If you connect them, the whole charge Q will be emptied from the inner sphere
 

Khimraj

Last Activity: 5 Years ago

potential becomes same on both spheres. So
k (Q - x) / R = k x /2R
Q - x = x/2
3x/2 = Q
x = 2Q/3
so charge flow = Q -x = Q/3
Hope it clears...........................................
 

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