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A point charge of 5 C is placed at point P as shown. A unit positive charge is taken from A to B along the circular path shown. Then the net work done by electostatic forces is (O is the centre of the circular path) (where k=9×10^9 N m^2 /C^2)Plzz explain\t+400k\t+4k\t-400k\t-4k

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define potential at a as va = k(5)*100/5. the 5 in the denominator is via trigonometry if you dont understand plz refer to 
+1 ncert or pythagoras from class 8. next define potential at p as vb=k(5)*100/1. now va-vb. and voila the answer

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