Electrostatics> In electrostatics E=-dV/dR where E=electr...

In electrostatics E=-dV/dR where E=electric field and V=electric potential. Then how can there be E on equtorial axis of an electric dipole where V is zero?

sujeesh b , 11 Years ago

Grade

2 Answers

Ashish Gupta

$dV = -\int\overrightarrow{E}.d\overrightarrow{r} = -[Ex dx + Ey dy + Ez dz]$
Hence, $Er = - dV/dr$

On equatorial axis of an electric dipole, electric field in the direction of radius vector i.e. Er = 0 as you can verify that V is 0 on equatorial axis and hence $dV/dr = 0$ .
Electric field is there but it is actually perpendicular to radius vector.

Last Activity: 11 Years ago

Rishi Sharma

Dear Student,
Please find below the solution to your problem.

Hence,

On equatorial axis of an electric dipole, electric field in the direction of radius vector i.e. Er = 0 as you can verify that V is 0 on equatorial axis and hence [dV/dr = 0] . Electric field is there but it is actually perpendicular to radius vector.

Thanks and Regards

Last Activity: 5 Years ago