Electrostatics> two parallel plates have charges Q1 and Q...

two parallel plates have charges Q1 and Q2 on them and the capacitance is C.The PD between them is????

Mostafijur Rahaman , 10 Years ago

Grade 12

1 Answers

Arun Kumar

Last Activity: 10 Years ago

Hi Mostafijur,

Let the plates be a,b

$\\ Q_a=Q_1 \\Q_b=Q_2 \\Q_{a,left}+Q_{a,right}=Q_1 \\Q_{b,left}+Q_{b,right}=Q_2 \\Q_{a,left}=Q_{b,right} \\Q_{a,right}+Q_{b,left}=0 \\=>Q_{a,left}=(Q_1+Q_2)/2 \\=>Q_{a,right}=(Q_1-Q_2)/2 \\=>Q_{b,left}=(Q_2-Q_1)/2$

Now the internal two sides will act as capacitor with charge

$\\Q_{b,left} \,or \,Q_{a,right} \\ so,|E|=|Q_{b,left}/C|$

Direction you can find .

Thanks & Regards

Arun Kumar

IIT Delhi

Askiitians Faculty

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Electrostatics> two parallel plates have charges Q1 and Q...

two parallel plates have charges Q1 and Q2 on them and the capacitance is C.The PD between them is????

Mostafijur Rahaman , 10 Years ago

Arun Kumar

Provide a better Answer & Earn Cool Goodies

LIVE ONLINE CLASSES

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