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When a test charge is placed at the center of dipole then what will be the force on test charge by the charges of dipole?

Harsh rao , 6 Years ago
Grade 12
anser 1 Answers
Shubham Jain

Last Activity: 6 Years ago

Let lenght of dipole be 2L and charges be q and -q.
Now, p=q×2L
p/2q=L
 
F on test charge= 2kq/(L^2)
                             = 2k4(q^2)/(p^2)
 
 

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