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Can you pls tell me the derivation of relation b/n energy differences Dq for octahedral, tetrahedral and sq. planar d orbital splitting?

varid gupta , 12 Years ago
Grade 12
anser 1 Answers
Aman Bansal

Last Activity: 12 Years ago

Dear VArid,

One of the important aspects of CFT is that not all ligands are identical when it comes to causing a separation of the energy of the d-orbitals. For transition metal compounds, there is clear evidence for this from the multitude of colours available for a given metal ion when the ligands or stereochemistry are varied. For octahedral complexes this is a reflection of the energy difference between the higher dz2, dx2-y2 (eg subset) and the dxy, dyz, dxz (t2g subset).

It has been established that the ability of ligands to cause a large splitting of the energy between the orbitals is essentially independent of the metal ion and the SPECTROCHEMICAL SERIES is a list of ligands ranked in order of their ability to cause large orbital separations.

A shortened list includes: 

I- < Br- < SCN- ~Cl- < F- < OH- ~ ONO- < C2O42- < H2O 
NCS- < EDTA4- < NH3 ~ pyr ~ en < bipy < phen < CN- ~ CO 


When metal ions that have between 4 and 7 electrons in the d orbitals form octahedral compounds, two possible electron distributions can occur. These are referred to as either weak field - strong field or high spin - low spin configurations. 

Best Of luck

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