The coagulation of 100 mL of colloidal solution of gold is completely prevented by addition of 0.25 g of a substance ‘X’ to it, before adding 1 ml of 10% NaCl solution. The gold number of X is(A) 0.25 (B) 25 (C) 250 (D) 2.5
Amit Saxena , 11 Years ago
Grade upto college level
1 Answers
Radhika Batra
Last Activity: 11 Years ago
Amt. of protective colloid added in milligrams = 0.25 × 1000 = 250
Hence By definition, the protective colloid required for 10 ml. =250/100×10=25
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