A stone released with zero velocity from the top of a tower, reaches the ground in 4 sec. The height of the tower is (g = 10m /s2)(a)20 m(b) 40 m(c) 80 m(d) 160 m
Hrishant Goswami , 11 Years ago
Grade 10
1 Answers
Amit Saxena
Last Activity: 11 Years ago
(c) Initial velocity (u) = 0; Time (t) = 4 sec and gravitational acceleration (g) = 10 m/s2. Height of tower h= ut+ 1/2 gt^2= (0×4 )+1/2×10× (4)^2 = 80 m.
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