Apiston filled with 0.04 mol of an ideal gas expands reversibly from50.0 mL to 375 mL at a constant temperature of 37.0°C. As it doesso, it absorbs 208J of heat. The values of q and w for the processwill be :(R= 8.314 J/mol K) (In 7.5 = 2.01)A) q= + 208 J, w = - 208 JB) q= - 208 J, w = - 208 JC) q= - 208 J, w = + 208 JD) q= + 208 J, w = + 208 J
Raghav , 10 Years ago
Grade 12
2 Answers
Avinash
Last Activity: 9 Years ago
For isothermal process, ? U = 0
Process is isothermal reversible expansion, hence dE =0
U = 0.
So, Using 1stlaw of thermodynamics
q = -W
or
w = -q = -208 J
Vaibhav saxena
Last Activity: 5 Years ago
For isothermal process, ? U = 0Process is isothermal reversible expansion,hence dE =0U = 0.So, Using 1stlaw of thermodynamicsq = -Worw = -q = -208 J
so our ans. is q=+280Jand w=-280J
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