Arun
Last Activity: 4 Years ago
The initial momentum is zero.
let m1=3 kg m2=1 kg & their velocities be v1 & v2 respectively.
according to conservationh of momentum
m1v1 + m2v2 = 0
3v1 + v2 = 0
v2 = -3v1
also,
0.5m1v22 + 0.5m2v22 = 24000
m1v12 + m2v22 = 4800
3v12 + v22 = 4800
3v12 +(-3v1)2 = 4800
12v12 = 4800
v1 = 20
v2 = -60 (opp. direction)
KE of m2 is 1800.