Options are:1. Activation enthalpy to form C is 5kJ mol^-1 less than to form D.2. D is kinetically stable product.3. C is thermodynamically stable product.4. Formation of A and B from C has highest enthalpy of activation.This question was given in JEE Main April 2019. The correct option given in the official answer key is 1. But I have a doubt if it’s not correct. Can you confirm it please?
Ayush Deotare , 5 Years ago
Grade 12
2 Answers
Saurabh Koranglekar
Last Activity: 4 Years ago
Vikas TU
Last Activity: 4 Years ago
Dear student
Activation enthalpy for C=20−5=15 kJ/mol
Activation enthalpy for D=15−5=10 kJ/mol.
so correct option is C.
Good Luck
Cheers
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