Incenter of the triangle is given by the formula, I = (ax1 + bx2 + cx3 )/(a+b+c) , (ay1 + by2 + cy3 )/(a+b+c) The given lines, x = 1, y = 1 and x + y = 1 intersect each other at points A (1, 1), B (0, 1) and C (1, 0).
we, have,
a = BC = √2
b = AC = 1
c = AB = 1
Therefore, the incenter is given by, I = (0.707, 0.707)
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free
Enter text here...
Other Related Questions on Engineering Entrance Exams