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The magnitude of the force developed by raising the temperature from 00 °C to 100100 °C of the iron bar of 11.0000 m long and 11 cm2cm^2 crosssectioncross-section when it is held so that it is not permitted to expand or bend isaisa = 105/10^-5/°C and Y = 10111011 N/m2N/m^2

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Jayant Kumar , 10 Years ago
Grade 11
anser 2 Answers
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Arun

Last Activity: 4 Years ago

The expression for force is F= Y x A x α x ΔT where Y is the Young's modulus, A the area of cross section, α the coefficient of linear expansion and ΔT is temperature difference.It is independent of length.

F = 1011 N/m2 x 1 x 10−4 m2 x 10−5 /
°C x 100 °C
= 10
4 N

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Vikas TU

Last Activity: 4 Years ago

Expression of force is F=×Y×A×α×ΔT where Y is the Young's Modulus.
∴F=10^11]cfracNm^2×1×10^−4m^2 ×10^−5×100°C
F=10^4 N
The magnitude of force =10^4 N

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