Flag General Physics> Rotational Mechanics...
question mark

Three identical uniform rods each of length 40cm and mass 2kg form an equilateral triangle. Find the moment of inertia of this system about an axis passing through one corner ?

 

Thanks in advance !

Sudheesh Singanamalla , 14 Years ago
Grade 12
anser 2 Answers
vikas askiitian expert

Last Activity: 14 Years ago

let ABC is the triangle formed by these rods then we have to find moment of inertia any about vertex , let vertex be A...

then , rod AB & AC will have same moment of inertia about end A ,

IAC = IAB = mL2/12 + mL2/4 = mL2/3

moment of inertia of BC  = mL2/12 + md2                     (d is perpendicular distance from axis of rotation)

      from triangle ABC , d = Lcos30

         IBC = mL2/12 + 3mL2/4 = 10mL2/12

net moment of inertia = IAB+IBC+IAC

                     Inet   =18mL2/12 = 3mL2 /2

                    Inet = 0.48kg-m2

approve my ans if u like it

Sudheesh Singanamalla

Last Activity: 13 Years ago

Thanks a Lot

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...