Flag General Physics> dimensions and units...
question mark

there are two more questions which i dint get.....the questions are as follows:-

1]the pressure of  liquid column depends on its height h, the density p[its the symbol of density],acceleration due to gravity g,show that p=h [symbol of density]p g by dimensional method.(give constant k=1)

2]express a pressure of 50 N/metre square in terms of dyne/cm square.

urgently needed for the test tht is conducted tomorrow...............

Ashwathy Menon , 15 Years ago
Grade Upto college level
anser 3 Answers
AskiitianExpert Shine

Last Activity: 15 Years ago

Hi

Take, P= k x ha x Þb x gc .

dimensions of P are kg/ms2 . Write the dimensions of h, g & Þ .

h=m , g=m/s2 , Þ= kg/m3

Equate the power of each i.e of m, kg and sec on the left hand side to rt hand side. U ll get three equations, solve them for three variables. U ll get the final answer as a=b=c=1 .

therefore P=hÞg as k=1

AskiitianExpert Shine

Last Activity: 15 Years ago

Ans 2:

Units of force
  newton
(SI unit)
dyne kilogram-force,
kilopond
pound-force poundal
1 N ≡ 1 kg·m/s² = 105 dyn ≈ 0.10197 kp ≈ 0.22481 lbf ≈ 7.2330 pdl
1 dyn = 10−5 N ≡ 1 g·cm/s² ≈ 1.0197×10−6 kp ≈ 2.2481×10−6 lbf ≈ 7.2330×10−5 pdl
1 kp = 9.80665 N = 980665 dyn gn·(1 kg) ≈ 2.2046 lbf ≈ 70.932 pdl
1 lbf ≈ 4.448222 N ≈ 444822 dyn ≈ 0.45359 kp gn·(1 lb) ≈ 32.174 pdl
1 pdl ≈ 0.138255 N ≈ 13825 dyn ≈ 0.014098 kp ≈ 0.031081 lbf ≡ 1 lb·ft/s²

1 Newton=  105dynes and 1 m = 100cm , therefore 1m2 = 104cm2 .

therefore 50N/m sq = 50 x 105 / 104 dynes /cm sq, hence answer is 500.

anshul dixit

Last Activity: 14 Years ago

u can use..........M1/M2=1000  L1/L2=100 T1/T2=1

n1ui=n2u2..........take the dymensional formula of newton/metresquare...

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...