If two soap bubbles of different radii are connected by a tube then, what happen..?

The excess pressure inside the soap bubble is inversely proportional to radius of soap bubble i.e.P ∝1/ r, r being the radius of bubble. It follows that pressure inside a smaller bubble is greater than that inside a bigger bubble. Thus, if these two bubbles are connected by a tube, air will flow from smaller bubble to bigger bubble and the bigger bubble grows at the expense of the smaller one.

Approved

Air flows from
the bigger bubble to the smaller bubble till the sizes become equal

Approved

air flows from smaller bubble to bigger bubble...hence,smaller bubble gets smaller and bigger bubble gets even bigger

Answer Details:

The excess pressure inside the soap bubble is inversely proportional to radius of soap bubble i.e.P ∝1/ r, r being the radius of bubble. It follows that pressure inside a smaller bubble is greater than that inside a bigger bubble. Thus, if these two bubbles are connected by a tube, air will flow from smaller bubble to bigger bubble and the bigger bubble grows at the expense of the smaller one

When these bubbles are joined through tube..the smaller bubble(with more pressure) gets its size decresed as the time passes by..and large bubble(with less pressure) gets its size increased..The smaller bubble size decreases upto that extent when the radius of bubble becomes infinity..(i.e...it becomes flat with respect to tube)

Dear Student,
Please find below the solution to your problem.

Pressure inside a bubble =Po​ + 4S/R​
When they are connected using a tube then, as smaller bubbles {due to small radius} has higher pressure, the air flows from smaller bubble to bigger bubble until the smaller bubble vanishes completely.

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