A BREAKING STRESS OF THE MATERIAL OF A WIRE IS102 N/M2 . THE MAXIMUM LENGTH OF THE WIRE FOR WHICH IT BREAKS UNDER ITS OWN WEIGHT WILL BE (DENSITY OF MATERIAL IS2 X 103 KG/M3)?
ABHISHEK VASHIST , 10 Years ago
Grade 12th pass
2 Answers
Vasantha Kumari
Last Activity: 10 Years ago
Yash Chourasiya
Last Activity: 4 Years ago
Dear Student
Here the weight of the wire will be ALρg Stress due to its weight = W/A = Lρg Therefore, Breakdown Stress = Lρg 8 * 106 = L * 2*106 * 9.8 L = 40*10-2 m
I hope this answer will help you. Thanks & Regards Yash Chourasiya
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