From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle to hit the ground is n time that taken by it to reach the highest to its path. Show that 2gH =nu²(n-2)

Dear student,We know time to reach maximum height t1=u/g. t2 is time to reach ground is given by equation:-h=ut2 - 1/2 * g*t^2Given that t2=nt1 , putting value of t2 in above equation, we get 2gh=nu^2(n-2).Thanking you, Soumya Ranjan Mohanty.

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