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The escape velocity of projection from the earth is approximately (R = 6400 km)(a) 7 km/sec(b) 112 km/sec(c) 12.2 km/sec(d) 1.1 km/sec

Bibhu Ranjan Chakraborty , 3 Years ago
Grade 12th pass
anser 1 Answers
Unicorn

Last Activity: 3 Years ago

1/2 mv^2= GMm/r 
 
V escape =root 2GM/r
Putting values of radius and constants we get 
Vescape =11.2 km/sec
 

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