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What is the two wavelengths of the series of triply ionized beryllium (Z=4)

Pally , 2 Years ago
Grade 12
anser 1 Answers
Jagrat

Last Activity: 2 Years ago

Since the radiation of the Balmer series ends with n= 2.
Hence two longest wavelengths are the radiations corresponding to 
n = 3 to n= 2
And n = 4 to n =2
 
Now  find (E3- E2) = - (13.6 ev) 4² ( 1/9 -  1/4)
Then
Lambda = h c /E
Similarily for
(E4- E2)

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