A particle of mass m is moving with a uniform velocity v1. It is given an impulse such that its velocity becomes v2. The impulse is (equal to(a) m [|v2| = |v1|(b)m[v22 - v=12](c) m[v1 + v2](d)[v2 – v1]
Simran Bhatia , 11 Years ago
Grade 11
1 Answers
Hrishant Goswami
Last Activity: 11 Years ago
(d)
Impulse = final momentum - initial momentum = m(v2-v1)
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