how can we find bond angle? Is there any forluma?pls. Explain with example.

bond angle of a compound can be found by gathering the information about its hybridisation?

for example: for NH₃, its hybridisation is sp₃,so bond angle is 104.5^0.

Dear Vaishal,

 One can never get correct bond angle by any formula always, bcoz of lone pair repulsions or due to lack of electrons, but here is a hyb. table, which would help you.

VSEPR table

The bond angles in the table below are ideal angles from the simple VSEPR theory, followed by the actual angle for the example given in the following column where this differs. For many cases, such as trigonal pyramidal and bent, the actual angle for the example differs from the ideal angle, but all examples differ by different amounts. For example, the angle in H₂S (92°) differs from the tetrahedral angle by much more than the angle for H₂O (104.5°) does.

Bonding electron pairs	Lone pairs	Electron domains	Shape	Ideal bond angle (example's bond angle)	Example	Image
2	0	2	linear	180°	CO2
3	0	3	trigonal planar	120°	BF3
2	1	3	bent	120° (119°)	SO2
4	0	4	tetrahedral	109.5°	CH4
3	1	4	trigonal pyramidal	107.5°	NH3
2	2	4	angular	104.5°	H2O
5	0	5	trigonal bipyramidal	90°, 120°	PCl5
4	1	5	seesaw	180°, 120°, 90° (173.1°, 101.6°)	SF4
3	2	5	T-shaped	90°, 180° (87.5°, < 180°)	ClF3
2	3	5	linear	180°	XeF2
6	0	6	octahedral	90°, 180°	SF6
5	1	6	square pyramidal	90° (84.8°), 180°	BrF5
4	2	6	square planar	90° 180°	XeF4
7	0	7	pentagonal bipyramidal	90°, 72°	IF7

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