An atom has electronic configuration 1s2 2s2 2p6 3s2 3p6 3d3 4s2, you will place it in which group of periodic table ???

1. Fifth 2. Fifteenth

3. Second 4. Third

Please solve with explanation and not by atomic number z=23 and this belong to this group like that............

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The atomic configuration given =  1s2 2s2 2p6 3s2 3p6 3d3 4s2
We know that for neutral atoms the number of electrons is equal to the atomic number of the element.
Total no of electron = 2+2+6+2+6+3+2 = 23
=> atomic number of this element is 23
This number corresponds to Vanadium which is a transition metal located in fourth row, group 5 of the periodic table.