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KmNO4 reacts with oxalic acid as MnO4-+C2042- ------------>Mn2++CO2. Hence 50 ml of 0.04 M KMnO4 in acidic medium is chemically equivalent to?
OPTIONS:
  • 100 ml 0.1 M oxalic acid
  • 50 ml 0.1 M oxalic acid
  • 50 ml 0.2 M oxalic acid
  • 25 ml 0.1 M oxalic acid

ASh , 7 Years ago
Grade 12th Pass
anser 1 Answers
Sandeep Bhamoo

Last Activity: 7 Years ago

Since in a reaction Eq.(a)=Eq.(b). Eq(KMnO4)= n-f × M ×V = 5×50×0.04 = 10 Eq(C2O4)= 10 = 2×(M×V) —> M×V=5. That is in second option
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