Inorganic Chemistry> why is K2[NiF6] diamagnetic it should be ...

why is K2[NiF6] diamagnetic
it should be paramagnetic with sp3d2 hybridisation

suvidhi mehta , 7 Years ago

Grade 12

5 Answers

Arun

Last Activity: 7 Years ago

Their is no unpaired electron so this complex is diamagnetic in nature....... Regards.....Arun (askIITians forum expert)

Approved

suvidhi mehta

Last Activity: 7 Years ago

4 unpaired electrons should be present since F- is a weak field ligand pairing wont take place

is it an exceptional case to general theory

abhishek mishra

Last Activity: 7 Years ago

It is a diamagnetic complex, Inspite of presence of weak field ligand there occurs forced pairing due to more effective nuclear charge of Ni4+ cation. This complex is d2sp3 hybridised. Ref: ( structural inorganic chemistry by Wai Kee Lee)

VIGNESH

Last Activity: 5 Years ago

THE OXIDATION NUMBER OF METAL IS INCREASES CORRESPONDINGLY THE ENERGY GAB BETWEEN THE t2g AND Eg ARE INCREASES. HENCE THE FREEL ELECTRON ON THE METAL(NICKEL) IS FILING FIRST IN THE t2g ORBITALS NEXT Eg ORBITAL. HERE THE 6 ELECTRONS ON THE METAL IS FILLING IN t2g ORBITAL . SINCE THERE ARE NO UNPAIRED ELECTRON IN THIS COMPLEX. SO THIS COUMPOUND IS DIAMAGNETIC.

Rishi Sharma

Last Activity: 5 Years ago

Dear Student,
Please find below the solution to your problem.

THE OXIDATION NUMBER OF METAL IS INCREASES CORRESPONDINGLY THE ENERGY GAB BETWEEN THE t2g AND Eg ARE INCREASES.
HENCE THE FREEL ELECTRON ON THE METAL(NICKEL) IS FILING FIRST IN THE t2g ORBITALS NEXT Eg ORBITAL.
HERE THE 6 ELECTRONS ON THE METAL IS FILLING IN t2g ORBITAL .
SINCE THERE ARE NO UNPAIRED ELECTRON IN THIS COMPLEX.
SO THIS COUMPOUND IS DIAMAGNETIC

Thanks and Regards