what will be its answer .....its a bit confusing one....∫(Sin X2)2.(CosX2)2dx

Dear Pawan deep,

Ans:- f(x)=∫(sinX²)²(cosX²)²dx

             =1/4∫(sin2X²)²dx

               =1/16∫(1 - cos4X²)²dx

                =1/16∫(1 - 2cos4X²+ cos²4X²)dx

                =1/16∫(3/2 - 2cos4X² +1/2cos8X²)

                  =3/32 X -1/8∫cos4X²dx +1/16 ∫cos8X²

Now the value of the 2nd and the third integral can not be found unless it is a definte integral.

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