Badiuddin askIITians.ismu Expert
Last Activity: 15 Years ago
Dear harshit agarwal
∫(dx/(x(xn +1))
multiply and devide by xn-1
integral will become
∫(xn-1dx/(xn(xn +1))
put xn=t
nxn-1dx=dt
now integral will become
1/n∫(dt/(t(t +1))
=(1/n)∫(dt/[(t +1/2)2-(1/2)2]
this can be easly solve
by using the formula for
∫(dt/[(t)2-(a)2]
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Badiuddin