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Let f (x) =\nx\n0\n( u22u+1 )du then find the least value of f (x) in [-1,1].\n-2u+2

raju , 10 Years ago
Grade 12
anser 1 Answers
Sher Mohammad

Last Activity: 10 Years ago 


its a monotonically increasing function.

f'(x)=(x+1)^2=0, x=-1

minima value=-1/3+1-1=-1/3


Sher Mohammad,
B.tech, IIT Delhi

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