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We have to find the integral of 3x⁴-1/(x⁴+x+1)²options are 1) x/(x⁴+x+1)2) -x/(x⁴+x+1)3) x+1/(x⁴+x+1)4) -x-1/(x⁴+x+1)

Neha Sharma , 6 Years ago
Grade 12
anser 1 Answers
Aditya Gupta

Last Activity: 6 Years ago

Divide the numerator and denominator by x^2.
We get
(3x^2-1/x^2)/(x^3+1+1/x)^2
Now put x^3+1+1/x= y
So integral becomes dy/y^2
So final answer is
-x/(x^4+x+1)+C

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