what is the integration of (sin-1x)2?

?(sin^-1x)²dx

put sin^-1x=t => x=sint

dx=cost dt

?t²costdt

=t²sint-?2t.sintdt

=t²sint-2[-tcost+?costdt]

=t²sint+2tcost-2sint +C

=(sin^-1x)²x+2sin^-1xv(1-x²)-2x+ C

Thanks & Regards

Rinkoo Gupta

AskIITians Faculty

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