Last Activity: 13 Years ago
for all x>1, x^x^x^x...∞→∞,therefore your method of solution technically breaks down. This is like, for example, the formula
rn1+x+x^2+x^3...∞ =1/1-x breaks down when lxl ≥1
Last Activity: 13 Years ago
see if you replace 2 by 6, the the answer is not root 2 but 6th root of 6.. and this is the only approach to this. You are absolutely correct.
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