Askiitians Expert Bharath-IITD
Last Activity: 14 Years ago
Dear Madhu,
Let the two isolated poles of equal pole strengths are separated by distance L say.
Now consider a point x assuming first pole is at origin.
Then the net force experienced by a unit north pole placed at this point is given by the difference of the forces due to the two poles.
Fnet= F1 - F2
= K{ (1/x)^2 - (1/L-x)^2 }
Where K is a constant given by similar terms in both F1 and F2 i.e,
{(munot/ 4* pi)*1* pole strength of the isolated pole}.
If we equate it to Zero
Then we would get x = L/2.
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Adapa Bharath