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a proton of mass m and charge q enters a magnetic field B with velocity v at an angle x with the direction of B what will be the radius of curvature of resulting path

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Vishesh , 7 Years ago
Grade 12th pass
anser 1 Answer
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Eshan

Last Activity: 6 Years ago

Dear student,

Force acting on proton=left| qvecv× vecBright|=qvBsinx
This force causes the centripetal acceleration of the proton. Hence

qvBsinx=dfracmv sinx ^2R
implies R=dfracmv sinxqB

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