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A rod of lenght L,along eastwesteast-west direction is dropped from a height H. If B be the magnetic field due to earth at that place and angle of dip is delta,then what is the magnitude of induced emf across two end of the rod when the rod reaches the earth?

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sachin jeengar , 8 Years ago
Grade 12
anser 3 Answers
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Timir Patel

Last Activity: 8 Years ago

given:-
B is the magneetic field and X is the angle of dip
then horizontal magnetic field is BcosX
length of rod is L
velocity of the rod falling is 2gH½
induced emf is = Blv = Bcosx.L.2gH1/2

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Adarsh sharma

Last Activity: 6 Years ago

When a rod falls,it cuts the horizontal component of earth`s magnetic field. As a result of which change in magnetic flux takes place and emf is induced. e=BlvSince, u=0 a =+g As v=u+gt v= gt e = Blgt So e is directly proportional to the time

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Rishi Sharma

Last Activity: 4 Years ago

Dear Student,
Please find below the solution to your problem.

B is the magneetic field and X is the angle of dip
then horizontal magnetic field is BcosX
length of rod is L
velocity of the rod falling is 2gH½
induced emf is = Blv = Bcosx.L.2gH1/2

Thanks and Regards

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