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A thin conducting ring of mass 'm' carrying a charge q can rotate freely about its own vertical axis. at the initial moment the ring was at rest and no magnetic field was pesent. At instant t=0, a uniform magnetic field is switched on which is vertically downward and increasing wrt time according to B(t).find1. angular accelaration of ring and its direction as seen from above2.power developed by forces acting on ring as funcion of time.

Kevin Nash , 10 Years ago
Grade upto college level
anser 1 Answers
ROSHAN MUJEEB

Last Activity: 4 Years ago


Solution :
|e|=∣∣∣dϕ/dt∣∣∣=SdB/dt=(πa2)B0

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