Magnetism> Figure shows a circular wire loop of radi...

Figure shows a circular wire loop of radius 0.5 carriying current i placed in a perpendicular magnetic field 1/3. (a) Consider a small part dl of the wire. The force on this part of wire exerted by the magnetic field in the radially outward direction is idl/N. Find N.

AJS Thevel , 8 Years ago

Grade 12

1 Answers

ROSHAN MUJEEB

Last Activity: 4 Years ago

Fdl=i×dl×B towards centre. (By cross product rule)
(b) Let the length of subtends an small angle of 2θ at the centre
Here,
2Tsinθ=i×dl×B
2Tθ=i×a×2θ×B [As θ→0,sinθ≈0]
T=i×a×B
T=a i B
Force of compression on the wire =iaB

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Magnetism> Figure shows a circular wire loop of radi...

Figure shows a circular wire loop of radius 0.5 carriying current i placed in a perpendicular magnetic field 1/3. (a) Consider a small part dl of the wire. The force on this part of wire exerted by the magnetic field in the radially outward direction is idl/N. Find N.

AJS Thevel , 8 Years ago

ROSHAN MUJEEB

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