magnetic field is 37.2..at the center of the circular coil of radius 42cm..that has 100 turnsis
sai kumar432 , 9 Years ago
Grade 12
Magnetism> magnetic field is 37.2..at the center of ...
2 Answers
SHANMUKESHWAR
Last Activity: 9 Years ago
radius=42*10^-2
B=37.2
turns=100
B=4*3.14*I*100/2*42*10^-2
B=I*0.149*10^-3
I=37.2/0.149*10^-3
I=2.49*10^5A
Prabhakar ch
Last Activity: 9 Years ago
Dear Sai kumar
Radius, R=42*10^-2
Magnetic field, B=37.2
turns=100
B=4*3.14*I*100/2*42*10^-2
B=I*0.149*10^-3
I=37.2/0.149*10^-3
I=2.49*10^5A
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