ROSHAN MUJEEB
Last Activity: 4 Years ago
The time period of oscillations of magnet
T=2πMHI ....(i)
where,I=moment of inertia of magnet
=12mI2(m, being the mass of magnet)
M=pole strength×L
andH=horizontal component of Earth's magnetic field.
When the three equal parts of magnet are placed on one another with their like poles together, then
I′=121(3m)(3L)2×3=1219mL2=9I
andM′=Pole strength×3L×3=M
Hence,T=2πMHI/9⇒T′=31×T
T′=32s