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A flowerpot falls from a windowsill 25.0 m above the sidewalk.(a) how fast is the flowerpot moving when it strikes the ground?(b) how much time does a passerby on the sidewalk below have to move out of theway before the flowerpot hits the ground?

sachin singh , 14 Years ago
Grade 12
anser 1 Answers
vikas askiitian expert

Last Activity: 14 Years ago

t is the time taken by flower pot to reach the bottom

     t= sqrt2s/g=sqrt5

 now using   v=u +at

                  v=10sqrt5 m/s (velocity with which flower pot hits the ground)

 

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