A flowerpot falls from a windowsill 25.0 m above the sidewalk.(a) how fast is the flowerpot moving when it strikes the ground?(b) how much time does a passerby on the sidewalk below have to move out of theway before the flowerpot hits the ground?
sachin singh , 14 Years ago
Grade 12
1 Answers
vikas askiitian expert
Last Activity: 14 Years ago
t is the time taken by flower pot to reach the bottom
t= sqrt2s/g=sqrt5
now using v=u +at
v=10sqrt5 m/s (velocity with which flower pot hits the ground)