find the average velovity of a projectile projected with vekocity 'u'm/s making an angle theta between its stsrting point and highest point?

Dear Rajan

See the pic for solution

All the best.

AKASH GOYAL

AskiitiansExpert-IITD

Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation.

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar  respectively : Click here to download the toolbar..

average velocity = total displacement / total time

H is the maximum height and R is the horizontal range of projectile ....

at highest point, projectile is H m above in verticle  and R/2 m  far in horizontal direction from the point of projection..

displacement = sqrt{ H^2 + (R/2)^2} ={u^2sin@ sqrt(1+3cos^2@) } /g

time taken by projectile to reach to maximum height is t = T/2 =usin@/g

Vavg = usqrt( 1+3cos^2@)