find the average velovity of a projectile projected with vekocity 'u'm/s making an angle \"theta\" between its stsrting point and highest point?

Dear Rajan

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AKASH GOYAL

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Approved

average velocity = total displacement / total time

H is the maximum height and R is the horizontal range of projectile ....

at highest point, projectile is H m above in verticle  and R/2 m  far in horizontal direction from the point of projection..

displacement = sqrt{ H^2 + (R/2)^2} ={u^2sin@ sqrt(1+3cos^2@) } /g

time taken by projectile to reach to maximum height is t = T/2 =usin@/g

Vavg = usqrt( 1+3cos^2@)

Approved