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find the average velovity of a projectile projected with vekocity 'u'm/s making an angle theta between its stsrting point and highest point?

rajan jha , 14 Years ago

Grade 12

2 Answers

AKASH GOYAL AskiitiansExpert-IITD

Last Activity: 14 Years ago

Dear Rajan

See the pic for solution

All the best.

AKASH GOYAL

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vikas askiitian expert

Last Activity: 14 Years ago

average velocity = total displacement / total time

H is the maximum height and R is the horizontal range of projectile ....

at highest point, projectile is H m above in verticle and R/2 m far in horizontal direction from the point of projection..

displacement = sqrt{ H^2 + (R/2)^2} ={u^2sin@ sqrt(1+3cos^2@) } /g

time taken by projectile to reach to maximum height is t = T/2 =usin@/g

Vavg = usqrt( 1+3cos^2@)

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