a small block b is placed on a block a of mass 5kg and lenght 20cm.initially block b is near the right end of block a.a constant horizontal force of 10newton is applied on block aall the surfaces are assumed frictionlessfind the time elapsed before the block b seperates from block aplz help me

let the mass of block b is m_b....

force on lower block is F=10N....

accleration of system is a...

    (m_b+5)a = 10

         a= 10/(m_b+5) m/s²

now a seudo force acts on the upper block in opposite direction and its magnitude is f=(m_b)a...

 due to this force block moves in opposite direction with accleration a¹....

   m_ba¹=m_ba

      a¹=a=10/(5+m_b)

when the block covers a distance of 20cm then it separates out...

   0.2 = a¹t²/2

   t²  =  (0.4/a¹)=[0.04(5+m_b)]

   t=  0.2(5+m_b)^1/2

The block A will accelerate under the force 10 N applied on it. But the surfaces being frictionless, block B will remain stationary. Soblock B will separate from block A when block A has travelled a distance s equal to its length i.e. 20cm.For block A:u=0 m/s; a=Force/Mass=10/5=2NSo, v²=√(u²+2as)v=√2as=√(2*2*0.2)=0.894 m/sTherefore, v=u+at0.894=0+2t=>t=0.447 sec=0.45 sec