Aman Bansal
Last Activity: 13 Years ago
Dear Pankaj,
let origin is thier reference
1st particle is going awy fom origin. so, its phase is [sin inverse (a/3a)] i.e [sin inverse (1/3)]
similarly phase of 2nd particle is [-sin inverse(1/3)]
Hence the phase difference between above 2 paricles is [2sin inverse(1/3)]
Best Of luck
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Aman Bansal
Askiitian Expert