A simple pendulum is suspended from the ceiling of a car accelerating uniformly on a horizontal road.If the acceleration is a and length of the pendulum is l,find the time period of small oscillation about the mean position.
chandra shekhar mishra , 11 Years ago
Grade 12
3 Answers
Chetan Mandayam Nayakar
Last Activity: 11 Years ago
T=2pi√(l/(√(a2+g2)))
Yogita Bang
Last Activity: 11 Years ago
The car is accelerating in horizontal direction with acceleration a. The accleration due to gravity is g in downward direction.
Resultant acceleration a'' = (a2 + g2)1/2
Time period T=2pi(L/a'')1/2 =2pi{L/(a2+g2)1/2}
Kushagra Madhukar
Last Activity: 4 Years ago
Dear student,
Please find the solution to your problem.
The car is accelerating in horizontal direction with acceleration a. The accleration due to gravity is g in downward direction.
Resultant acceleration a'' = √(a2 + g2)
Time period T = 2π√(L/a'')= 2π√{L/√(a2+g2)}
Thanks and regards,
Kushagra
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