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The length of the second pendulum on the surface of earth is 1 m The length of seconds pendulum on the surface of moon where g is 1/6th value of g on the surface of earth

pallavi pradeep bhardwaj , 14 Years ago
Grade 12
anser 2 Answers
Rohith Gandhi

Last Activity: 14 Years ago

Dear Pallavi,

 

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Rohith Gandhi P

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the solution to your problem.
 
Tm = 2π√L/(g/6)
Hence, 2 = 2π√L/(g/6)
or, L = g/6π2
or, L = 0.167 m
 
Thanks and regards,
Kushagra

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