a particle starts falling from top of tower at t=0 simultaneously a car situated on ground some distance away starts moving towards the tower at a constant velocity of 5m/s the radius of curvature of the trajectory of particle as seen by observer in the jeep at some time t is 5/2*(17)3/2 metre ...FIND the time t in seconds.!!
Prakhar Srivastava , 11 Years ago
Grade 12
1 Answers
Akash Kumar Dutta
Last Activity: 11 Years ago
Dear Prakhar, the speed of the particle is= (-gt). j^ speed of car= (-5). i^ Relative velocity of the car= (-5).i^ + (gt).j^ relative acc for car= (g).j^ but v^2/R=g Find mod v and by putiing putting the value of value of v and R we get the ans. sorry I didnt proceeded since i didnt understood the value of R. Regards.
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