A particle moves along the x-direction with constant acceleration. The displacemnt, measured from a convenient position, is 2m at time t=0 and is zero when t=10sec. If vel. of the particle is momentary zero when t=6sec, determine the acceleration a and velocity v when t=10sec.

Dear Chilukuri

let convinient point is origin

 and initial velocity is u  in positive x direction

and acceleration is a in positive x direction

so

S= ut +1/2 * a* t²

-2 = u*10 +1/2  *a*100

-1/5 =u + 5a ....................1

and v=u+at

     0 =u+a*6

   u=-6a .......................2

solve equation 1 and 2

a=1/5

u=-6/5

so - sign tells that initial velocity is in the negative x dorection.

accleratin at time t = 1/5 m/sec2

velocity  v= u +at

               =-6/5 + 1/5 *10

              =4/5 m/sec

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